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At certain location in the northern hemisphere, the earth's magnetic field has a magnitude of 42?T and points down ward at 57º to vertical. The flux through a horizontal surface of area 2.5 m2 will be ?(Given : cos 33º = 0.839, cos 57º = 0.545)(1) 42 × 10?6 Wb(2) 42 × 10?6 Wb/m2(3) 57 × 10?6 Wb(4) 57 × 10?6 Wb/m2


At certain location in the northern hemisphere, the earth's magnetic field has a magnitude of 42?T and points down ward at 57º to vertical. The flux through a horizontal surface of area 2.5 m2 will be ?(Given : cos 33º = 0.839, cos 57º = 0.545)(1) 42 × 10?6 Wb(2) 42 × 10?6 Wb/m2(3) 57 × 10?6 Wb(4) 57 × 10?6 Wb/m2


Grade:upto college level

1 Answers

ROSHAN MUJEEB
askIITians Faculty 829 Points
2 years ago
when magnetic field passes through a surface, the amount of magnetic flux is calculated by multiplying the component of magnetic field along normal to the surface, with the area of the surface.

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