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At certain location in the northern hemisphere, the earth's magnetic field has a magnitude of 42?T and points down ward at 57º to vertical. The flux through a horizontal surface of area 2.5 m2 will be ?(Given : cos 33º = 0.839, cos 57º = 0.545)(1)\t42 × 10?6 Wb(2)\t42 × 10?6 Wb/m2(3)\t57 × 10?6 Wb(4)\t57 × 10?6 Wb/m2

Kevin Nash , 10 Years ago
Grade upto college level
anser 1 Answers
ROSHAN MUJEEB

Last Activity: 4 Years ago

when magnetic field passes through a surface, the amount of magnetic flux is calculated by multiplying the component of magnetic field along normal to the surface, with the area of the surface.

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