An infinitely long straight conductor is bent into into the shape as shown in the figure. It carries a current of I ampere and the radius of the circular loop is r meter. Then the magnetic induction at its centre will be?

Question

Arun · Answer

Dear Amrit I am getting my answer as B = mu * I *pi / 2 * pi *R + 1 Regards Arun (askIITians forum expert)

Manisha Kumari · Answer

Since dir. of magnetic field is opposite in both straight wire and loop so net mag field will be- B= uoI/2r - uoI/2pi×r = uoI(pi-1)/2pi×r

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An infinitely long straight conductor is bent into into the shape as shown in the figure. It carries a current of I ampere and the radius of the circular loop is r meter. Then the magnetic induction at its centre will be?

An infinitely long straight conductor is bent into into the shape as shown in the figure. It carries a current of I ampere and the radius of the circular loop is r meter. Then the magnetic induction at its centre will be?

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An infinitely long straight conductor is bent into into the shape as shown in the figure. It carries a current of I ampere and the radius of the circular loop is r meter. Then the magnetic induction at its centre will be?

An infinitely long straight conductor is bent into into the shape as shown in the figure. It carries a current of I ampere and the radius of the circular loop is r meter. Then the magnetic induction at its centre will be?

2 Answers

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Other Related Questions on Magnetism

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