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An electron accelerated by 200 V, enters in magnetic field. If its velocity is 100 m/s, then (e/m) for it will be.
(A) 1.75 * 10^10
(B) 1.75 * 10^11
(C) 1.75 * 10^9
(D) 1.75 * 10^6

mahmood , 6 Years ago
Grade 12th pass
anser 2 Answers
Vikas TU

Last Activity: 6 Years ago

The kinetic energy would be after accelerateed by 200 V would be:
0.5*mv^2 = eV
0.5*v^2/V = e/m
e/m = (0.5*100^2)/200 => 25.
 

Asha

Last Activity: 3 Years ago

According to the measurement by Thomson, the value of e/m is 1.77*10^11 C/kg. So without calculation we can say the value 

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