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an electric current i enters and leaves a uniform circular wire of radius a thrpugh diametrically opposite points. an charged particle q moving along the axis of the circular wire passes through its centre at speed v. the magnetic force acting on the particle when it passes through the centre has a magnitude ....ans is zero plzzzz explain

Navjyot Kalra , 12 Years ago
Grade 10
anser 1 Answers
Askiitians Tutor Team

To understand why the magnetic force acting on a charged particle moving through the center of a circular wire carrying an electric current is zero, we need to delve into some fundamental concepts of electromagnetism, particularly the relationship between electric currents and magnetic fields.

Magnetic Field Around a Current-Carrying Wire

When an electric current flows through a wire, it generates a magnetic field around it. The direction of this magnetic field can be determined using the right-hand rule: if you point your thumb in the direction of the current, your fingers curl around the wire in the direction of the magnetic field lines.

Analyzing the Situation

In this scenario, we have a uniform circular wire with a radius \( a \) through which a current \( i \) flows. The current enters and exits the wire at diametrically opposite points. Now, let’s consider the charged particle \( q \) moving along the axis of the circular wire and passing through its center at speed \( v \).

Magnetic Field at the Center

At the center of the circular wire, the contributions to the magnetic field from different segments of the wire must be analyzed. Since the wire is circular and the current is uniform, we can think about how the magnetic field generated by each infinitesimal segment of the wire interacts at the center point.

  • Each segment of the wire creates a magnetic field that points in a specific direction based on the right-hand rule.
  • However, for every segment of the wire on one side of the center, there is an equal segment directly opposite it on the other side of the center.
  • These opposite segments produce magnetic fields that are equal in magnitude but opposite in direction.

As a result, when you sum up all the magnetic fields from these segments at the center, they effectively cancel each other out. Therefore, the net magnetic field at the center of the wire is zero.

Magnetic Force on the Charged Particle

The magnetic force \( F \) acting on a charged particle moving in a magnetic field is given by the equation:

F = q(v × B)

Where:

  • \( F \) is the magnetic force.
  • \( q \) is the charge of the particle.
  • \( v \) is the velocity of the particle.
  • \( B \) is the magnetic field.

Since we established that the magnetic field \( B \) at the center of the circular wire is zero, substituting this into the equation gives:

F = q(v × 0) = 0

This means that the magnetic force acting on the charged particle is indeed zero when it passes through the center of the circular wire.

Visualizing the Concept

Think of it like this: imagine you have two people pushing against each other with equal force from opposite sides. The net effect is that they cancel each other out. Similarly, the magnetic fields from the wire segments cancel each other at the center, resulting in no net magnetic force acting on the charged particle.

In summary, the magnetic force on the charged particle is zero at the center of the circular wire due to the cancellation of the magnetic fields produced by the current flowing through the wire. This illustrates a fundamental principle in electromagnetism regarding the interaction of electric currents and magnetic fields.

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