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A wire of length L is bent round in the form of a coil having N turns of same radius. If a steady current I flows through it in clockwise direction, then find the magnitude and direction of the magnetic field produced at its centre. What I tried is attached in the picture.

A wire of length L is bent round in the form of a coil having N turns of same radius. If a steady current I flows through it in clockwise direction, then find the magnitude and direction of the magnetic field produced at its centre.
 
What I tried is attached in the picture.

 

Question Image
Grade:12

6 Answers

Arun
25750 Points
6 years ago
Dear student
Let the radius of the coil be r
As tge wire is bent round in the form of coil having N turns.
N * circumference of coil = lemgle of wire
L = 2 \pi r* N
Hence
r = L/ 2\piN
Now magnetic field is given by
B = \large \muo* N I/ 2r
B = \large \muo *\large \pi* N² I/L
Regards
Arun (askIITians forum expert)
Abjo Das
31 Points
6 years ago
WHy arent we using the solenoid formula?
Lorem ipsum
Dear student Let the radius of the coil be r As tge wire is bent round in the form of coil having N turns. N * circumference of coil = lemgle of wire L = 2 r* N Hence r = L/ 2 N Now magnetic field is given by B = o* N I/ 2r B = o * * N² I/L Regards Arun (askIITians forum expert)
Posted by Arun
Gitanjali Rout
184 Points
5 years ago
 
ear student
Let the radius of the coil be r
As tge wire is bent round in the form of coil having N turns.
N * circumference of coil = lemgle of wire
L = 2 \pi r* N
Hence
r = L/ 2\piN
Now magnetic field is given by
B = \large \muo* N I/ 2r
B = \large \muo *\large \pi* N² I/L
Regards,
Gitanjali Rout
184 Points
5 years ago
Dear student Let the radius of the coil be r As tge wire is bent round in the form of coil having N turns. N * circumference of coil = lemgle of wire L = 2 r* N Hence r = L/ 2 N Now magnetic field is given by B = o* N I/ 2r B = o * * N² I/L
Gitanjali Rout
184 Points
5 years ago
Dear student
Let the radius of the coil be r
As tge wire is bent round in the form of coil having N turns.
N * circumference of coil = lemgle of wire
L = 2 \pi r* N
Hence
r = L/ 2\piN
Now magnetic field is given by
B = \large \muo* N I/ 2r
B = \large \muo *\large \pi* N² I/L.
ankit singh
askIITians Faculty 614 Points
3 years ago
Let the radius of the coil be r
 
As tge wire is bent round in the form of coil having N turns.
 
N * circumference of coil = lemgle of wire
 
L = 2 πr* N
Hence
 
r = L/ 2πN
 
Now magnetic field is given by
B = μo* N I/ 2r
 
B = μo *π* N² I/L

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