A wire of length L is bent round in the form of a coil having N turns of same radius. If a steady current I flows through it in clockwise direction, then find the magnitude and direction of the magnetic field produced at its centre.

What I tried is attached in the picture.

Dear student

Let the radius of the coil be r

As tge wire is bent round in the form of coil having N turns.

N * circumference of coil = lemgle of wire

L = 2  r* N

Hence

r = L/ 2N

Now magnetic field is given by

B = o* N I/ 2r

B = o ** N² I/L

Regards

Arun (askIITians forum expert)

WHy arent we using the solenoid formula?
Lorem ipsum
Dear student Let the radius of the coil be r As tge wire is bent round in the form of coil having N turns. N * circumference of coil = lemgle of wire L = 2 r* N Hence r = L/ 2 N Now magnetic field is given by B = o* N I/ 2r B = o * * N² I/L Regards Arun (askIITians forum expert)
Posted by Arun

 

Dear student