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        A wire of length L is bent round in the form of a coil having N turns of same radius. If a steady current I flows through it in clockwise direction, then find the magnitude and direction of the magnetic field produced at its centre.  What I tried is attached in the picture.
one year ago

							Dear student
Let the radius of the coil be r
As tge wire is bent round in the form of coil having N turns.
N * circumference of coil = lemgle of wire
L = 2  r* N
Hence
r = L/ 2N
Now magnetic field is given by
B = o* N I/ 2r
B = o ** N² I/L
Regards

one year ago
							WHy arent we using the solenoid formula?Lorem ipsumDear student Let the radius of the coil be r As tge wire is bent round in the form of coil having N turns. N * circumference of coil = lemgle of wire L = 2 r* N Hence r = L/ 2 N Now magnetic field is given by B = o* N I/ 2r B = o * * N² I/L Regards Arun (askIITians forum expert)Posted by Arun

one year ago
							 ear studentLet the radius of the coil be rAs tge wire is bent round in the form of coil having N turns.N * circumference of coil = lemgle of wireL = 2  r* NHencer = L/ 2NNow magnetic field is given byB = o* N I/ 2rB = o ** N² I/LRegards,

one year ago
							Dear student Let the radius of the coil be r As tge wire is bent round in the form of coil having N turns. N * circumference of coil = lemgle of wire L = 2 r* N Hence r = L/ 2 N Now magnetic field is given by B = o* N I/ 2r B = o * * N² I/L

one year ago
							Dear student
Let the radius of the coil be r
As tge wire is bent round in the form of coil having N turns.
N * circumference of coil = lemgle of wire
L = 2  r* N
Hence
r = L/ 2N
Now magnetic field is given by
B = o* N I/ 2r
B = o ** N² I/L.


one year ago
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