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Grade: 12
        
A wire of length L is bent round in the form of a coil having N turns of same radius. If a steady current I flows through it in clockwise direction, then find the magnitude and direction of the magnetic field produced at its centre.
 
What I tried is attached in the picture.

 
5 months ago

Answers : (5)

Arun
11577 Points
							
Dear student
Let the radius of the coil be r
As tge wire is bent round in the form of coil having N turns.
N * circumference of coil = lemgle of wire
L = 2 \pi r* N
Hence
r = L/ 2\piN
Now magnetic field is given by
B = \large \muo* N I/ 2r
B = \large \muo *\large \pi* N² I/L
Regards
Arun (askIITians forum expert)
5 months ago
Abjo Das
31 Points
							
WHy arent we using the solenoid formula?
Lorem ipsum
Dear student Let the radius of the coil be r As tge wire is bent round in the form of coil having N turns. N * circumference of coil = lemgle of wire L = 2 r* N Hence r = L/ 2 N Now magnetic field is given by B = o* N I/ 2r B = o * * N² I/L Regards Arun (askIITians forum expert)
Posted by Arun
5 months ago
Gitanjali Rout
189 Points
							
 
ear student
Let the radius of the coil be r
As tge wire is bent round in the form of coil having N turns.
N * circumference of coil = lemgle of wire
L = 2 \pi r* N
Hence
r = L/ 2\piN
Now magnetic field is given by
B = \large \muo* N I/ 2r
B = \large \muo *\large \pi* N² I/L
Regards,
one month ago
Gitanjali Rout
189 Points
							
Dear student Let the radius of the coil be r As tge wire is bent round in the form of coil having N turns. N * circumference of coil = lemgle of wire L = 2 r* N Hence r = L/ 2 N Now magnetic field is given by B = o* N I/ 2r B = o * * N² I/L
one month ago
Gitanjali Rout
189 Points
							
Dear student
Let the radius of the coil be r
As tge wire is bent round in the form of coil having N turns.
N * circumference of coil = lemgle of wire
L = 2 \pi r* N
Hence
r = L/ 2\piN
Now magnetic field is given by
B = \large \muo* N I/ 2r
B = \large \muo *\large \pi* N² I/L.
one month ago
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