# A wire of length L is bent round in the form of a coil having N turns of same radius. If a steady current I flows through it in clockwise direction, then find the magnitude and direction of the magnetic field produced at its centre. What I tried is attached in the picture.

Arun
25758 Points
4 years ago
Dear student
Let the radius of the coil be r
As tge wire is bent round in the form of coil having N turns.
N * circumference of coil = lemgle of wire
L = 2 $\pi$ r* N
Hence
r = L/ 2$\pi$N
Now magnetic field is given by
B = $\large \mu$o* N I/ 2r
B = $\large \mu$o *$\large \pi$* N² I/L
Regards
Abjo Das
31 Points
4 years ago
WHy arent we using the solenoid formula?
Lorem ipsum
Dear student Let the radius of the coil be r As tge wire is bent round in the form of coil having N turns. N * circumference of coil = lemgle of wire L = 2 r* N Hence r = L/ 2 N Now magnetic field is given by B = o* N I/ 2r B = o * * N² I/L Regards Arun (askIITians forum expert)
Posted by Arun
Gitanjali Rout
184 Points
4 years ago

ear student
Let the radius of the coil be r
As tge wire is bent round in the form of coil having N turns.
N * circumference of coil = lemgle of wire
L = 2 $\pi$ r* N
Hence
r = L/ 2$\pi$N
Now magnetic field is given by
B = $\large \mu$o* N I/ 2r
B = $\large \mu$o *$\large \pi$* N² I/L
Regards,
Gitanjali Rout
184 Points
4 years ago
Dear student Let the radius of the coil be r As tge wire is bent round in the form of coil having N turns. N * circumference of coil = lemgle of wire L = 2 r* N Hence r = L/ 2 N Now magnetic field is given by B = o* N I/ 2r B = o * * N² I/L
Gitanjali Rout
184 Points
4 years ago
Dear student
Let the radius of the coil be r
As tge wire is bent round in the form of coil having N turns.
N * circumference of coil = lemgle of wire
L = 2 $\pi$ r* N
Hence
r = L/ 2$\pi$N
Now magnetic field is given by
B = $\large \mu$o* N I/ 2r
B = $\large \mu$o *$\large \pi$* N² I/L.
ankit singh
2 years ago
Let the radius of the coil be r

As tge wire is bent round in the form of coil having N turns.

N * circumference of coil = lemgle of wire

L = 2 πr* N
Hence

r = L/ 2πN

Now magnetic field is given by
B = μo* N I/ 2r

B = μo *π* N² I/L