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Grade 9Magnetism

A wire 88cm long bent into a circular loop is placed perpendicular to the magnetic field of flux density 2.5Wb/m(sq.). Within , 0.5s the loop is changed into a square of each side 22cm, and flux density is increased to 3Wb/m(sq). Calculate the value of emf induced .

Profile image of Jitender Pal
12 Years agoGrade 9
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Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Year ago

To find the induced electromotive force (emf) in the scenario you've described, we can apply Faraday's law of electromagnetic induction. This law states that the induced emf in a closed loop is equal to the negative rate of change of magnetic flux through the loop. Let's break down the problem step by step.

Step 1: Calculate the Initial Magnetic Flux

The initial configuration of the wire is a circular loop. The circumference of the circle is given as 88 cm, which allows us to find the radius and then the area of the circle.

  • First, convert the circumference to meters: 88 cm = 0.88 m.
  • The formula for the circumference of a circle is \( C = 2\pi r \). Rearranging gives us \( r = \frac{C}{2\pi} = \frac{0.88}{2\pi} \approx 0.14 \, \text{m} \).
  • Now, calculate the area \( A \) of the circle using \( A = \pi r^2 \):
    \( A \approx \pi (0.14)^2 \approx 0.061 \, \text{m}^2 \).
  • The initial magnetic flux \( \Phi_1 \) is given by \( \Phi_1 = B_1 \times A \), where \( B_1 = 2.5 \, \text{Wb/m}^2 \):
    \( \Phi_1 = 2.5 \times 0.061 \approx 0.153 \, \text{Wb} \).

Step 2: Calculate the Final Magnetic Flux

Next, we need to find the magnetic flux when the wire is reshaped into a square loop.

  • The side length of the square is given as 22 cm, which is 0.22 m.
  • The area \( A \) of the square is calculated as \( A = \text{side}^2 = (0.22)^2 = 0.0484 \, \text{m}^2 \).
  • The new magnetic flux \( \Phi_2 \) with the increased flux density \( B_2 = 3 \, \text{Wb/m}^2 \) is:
    \( \Phi_2 = B_2 \times A = 3 \times 0.0484 \approx 0.1452 \, \text{Wb} \).

Step 3: Determine the Change in Magnetic Flux

The change in magnetic flux \( \Delta \Phi \) is calculated as follows:

  • \( \Delta \Phi = \Phi_2 - \Phi_1 = 0.1452 - 0.153 = -0.0078 \, \text{Wb} \).

Step 4: Calculate the Induced EMF

According to Faraday's law, the induced emf \( \mathcal{E} \) can be calculated using the formula:

\( \mathcal{E} = -\frac{\Delta \Phi}{\Delta t} \), where \( \Delta t = 0.5 \, \text{s} \).

  • Substituting the values gives:
    \( \mathcal{E} = -\frac{-0.0078}{0.5} = 0.0156 \, \text{V} \) or 15.6 mV.

Final Result

The induced emf in the circuit when the loop is transformed from a circular shape to a square shape and the magnetic flux density is increased is approximately 15.6 mV.