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a tightly wound solenoid of radius a length l has n turns per unit length .it carries current i.
consider a length dx of solenoid at a dist x from one end this contains ndxturns and may be approximated as a current i n dx
write the mag field at the center of solenoid and integrate it under proper limits

Jitender Pal , 12 Years ago
Grade 9
anser 1 Answers
Askiitians Tutor Team

To find the magnetic field at the center of a tightly wound solenoid, we can start by considering the properties of the solenoid itself. A solenoid is essentially a coil of wire that generates a magnetic field when an electric current passes through it. The magnetic field inside a long solenoid is uniform and can be calculated using Ampère's Law. Let's break this down step by step.

Understanding the Magnetic Field in a Solenoid

For a solenoid with n turns per unit length, carrying a current i, the magnetic field B inside the solenoid can be derived from the following formula:

B = μ₀ * n * i

Here, μ₀ is the permeability of free space, approximately equal to 4π × 10⁻⁷ T·m/A. This formula assumes that the solenoid is long enough that the end effects can be neglected, which is a good approximation for tightly wound solenoids.

Considering a Differential Length

Now, let’s consider a small segment of the solenoid of length dx at a distance x from one end. This segment contains n dx turns and can be treated as a small solenoid itself, carrying the same current i.

The magnetic field produced by this small segment at the center of the solenoid can be expressed as:

dB = μ₀ * (n dx) * i

Integrating Over the Length of the Solenoid

To find the total magnetic field at the center of the solenoid, we need to integrate this expression over the entire length of the solenoid, from 0 to l:

B = ∫(dB) = ∫(μ₀ * n * i dx)

Now, we can substitute the limits of integration:

B = μ₀ * n * i ∫(dx) from 0 to l

Evaluating the integral gives us:

B = μ₀ * n * i * [x] from 0 to l = μ₀ * n * i * l

Final Expression for the Magnetic Field

Thus, the magnetic field at the center of the solenoid can be expressed as:

B = μ₀ * n * i

This result shows that the magnetic field inside a long solenoid is directly proportional to the number of turns per unit length and the current flowing through it. The longer the solenoid or the more turns it has, the stronger the magnetic field will be.

Key Takeaways

  • The magnetic field inside a long solenoid is uniform and can be calculated using the formula B = μ₀ * n * i.
  • By considering a small segment of the solenoid, we can integrate to find the total magnetic field at the center.
  • The magnetic field strength is influenced by both the current and the density of turns in the solenoid.

This understanding of magnetic fields in solenoids is fundamental in electromagnetism and has practical applications in devices like electromagnets, inductors, and transformers.

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