ROSHAN MUJEEB
Last Activity: 4 Years ago
Time period for oscillating magnet is
T=2πMBI.........(1)
where I is the moment of inertia,
M is the magnetic moment
M=x×l
x=polestrength
When the magnet is broken in two equal parts, the new magnetic dipole moment is
M′=2x×l=2M
I′=2ML12
=122M×(2L)2
=12×8ML2
=8I
New time period is
T′=2πM′BI′
TT′=M′I′
Putting all the values we get
TT′=41=21