A solenoid of length 0.5m and diameter 0.6cm consists of 1000 turns of fine wire carrying a current of 5×10^–³ ampere.the magnetic field in Weber/ m² at the ends of solenoid will be??

Question

Amritpal Singh Saini · Answer

The magnetic field near the ends is B=$ni/2 ( I have used $ as mu) , from the given information, we can put the values of $,n,i and on solving it gives as 31.4x10^-7 .....The value of $ is 4pi X 10^-7

tagurivarma · Answer

jeeA solenoid of length 0.5m and diameter 0.6m consists of1000 turns of fine wire carrying current of 5.0x10-3 Ampere.The magnetic field in Tesla at the ends of this solenoid will be:

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A solenoid of length 0.5m and diameter 0.6cm consists of 1000 turns of fine wire carrying a current of 5×10^–³ ampere.the magnetic field in Weber/ m² at the ends of solenoid will be??

A solenoid of length 0.5m and diameter 0.6cm consists of 1000 turns of fine wire carrying a current of 5×10^–³ ampere.the magnetic field in Weber/ m² at the ends of solenoid will be??

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A solenoid of length 0.5m and diameter 0.6cm consists of 1000 turns of fine wire carrying a current of 5×10^–³ ampere.the magnetic field in Weber/ m² at the ends of solenoid will be??

A solenoid of length 0.5m and diameter 0.6cm consists of 1000 turns of fine wire carrying a current of 5×10^–³ ampere.the magnetic field in Weber/ m² at the ends of solenoid will be??

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