A rod of lenght L,along east-west direction is dropped from a height H. If B be the magnetic field due to earth at that place and angle of dip is delta,then what is the magnitude of induced emf across two end of the rod when the rod reaches the earth?

When a rod falls,it cuts the horizontal component of earth`s magnetic field. As a result of which change in magnetic flux takes place and emf is induced. e=BlvSince, u=0 a =+g As v=u+gt v= gt e = Blgt So e is directly proportional to the time

Dear Student,
Please find below the solution to your problem.

B is the magneetic field and X is the angle of dip
then horizontal magnetic field is BcosX
length of rod is L
velocity of the rod falling is (2gH)½
induced emf is = Blv = Bcosx.L.(2gH)1/2

Thanks and Regards