Click to Chat
1800-2000-838
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A rod of lenght L,along east-west direction is dropped from a height H. If B be the magnetic field due to earth at that place and angle of dip is delta,then what is the magnitude of induced emf across two end of the rod when the rod reaches the earth?
given:-   B is the magneetic field and X is the angle of dip   then horizontal magnetic field is BcosX  length of rod is L  velocity of the rod falling is (2gH)½     induced emf is = Blv = Bcosx.L.(2gH)1/2 Â
When a rod falls,it cuts the horizontal component of earth`s magnetic field. As a result of which change in magnetic flux takes place and emf is induced. e=BlvSince, u=0 a =+g As v=u+gt v= gt e = Blgt So e is directly proportional to the time
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -