Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A ring is rotated about diametric axis in a uniform magnetic field perpendicular to the plane of the ring. If initially the plane of the ring is perpendicular to the magnetic field. Find the instant of time at which EMF will be maximum & minimum respectively :

A ring is rotated about diametric axis in a uniform magnetic field perpendicular to the plane of the ring. If initially the plane of the ring is perpendicular to the magnetic field. Find the instant of time at which EMF will be maximum & minimum respectively :

Grade:12th pass

2 Answers

Arun
25763 Points
one year ago
 ω = 2π/T = π/5 When ωt = π/2 ∵ ϕ will be minimum ∴ e will be maximum When ωt = π ∵ ϕ will have maximum ∵ e will be minimum
Vikas TU
14149 Points
one year ago
 
 
ω = 2π/T = π/5 When ωt = π/2 ∵ ϕ will be minimum ∴ e will be maximum
t = 2.5 sec 
wt = pi 
Phi will be max, e will be minimum 
t = 5 sec 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free