A rectangular coil pqrs of N turns length L and breadth B and carrying a current i is placed in a uniform magnetic field B with its longest side perpendicular and shorter sides parallel to the field as shown in the figure .compute the torque on the coil .the normal to its plane makes an angle Alpha with the field

Question

Arun · Answer

The area of cross-section of the coil is A = lb Now, the magnetic moment of the coil is m = IA = Ilb Now, we know that the torque acting on the coil is given as T = m x B = mb sin theta Here, θ is the angle between the magnetic field and the normal to the plane of the coil. Now, the magnetic field is directed perpendicular to the coil. Also, the normal to the coil will be perpendicular to the coil. So, the angle between the normal and the field is 0. Hence, the torque acting on the coil is zero.

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Magnetism

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship