Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

a proton of mass m and charge q enters a magnetic field B with velocity v at an angle x with the direction of B what will be the radius of curvature of resulting path

a proton of mass m and charge q enters a magnetic field B with velocity v at an angle x with the direction of B what will be the radius of curvature of resulting path

Grade:12th pass

1 Answers

Eshan
askIITians Faculty 2095 Points
3 years ago
Dear student,

Force acting on proton=\left| q(\vec{v}\times \vec{B})\right|=qvBsinx
This force causes the centripetal acceleration of the proton. Hence

qvBsinx=\dfrac{m(v sinx )^2}{R}
\implies R=\dfrac{mv sinx}{qB}

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free