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a proton of mass m and charge q enters a magnetic field B with velocity v at an angle x with the direction of B what will be the radius of curvature of resulting path

Vishesh , 7 Years ago
Grade 12th pass
anser 1 Answers
Eshan

Last Activity: 6 Years ago

Dear student,

Force acting on proton=\left| q(\vec{v}\times \vec{B})\right|=qvBsinx
This force causes the centripetal acceleration of the proton. Hence

qvBsinx=\dfrac{m(v sinx )^2}{R}
\implies R=\dfrac{mv sinx}{qB}

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