A proton and an α – particle are accelerated with

Question

A proton and an α – particle are accelerated with same potential difference and they enter in the region of constant magnetic field B perpendicular to the velocity of particles. Find the ratio of radius of curvature. Of proton to the radius of curvature of α – particle

Deepak Patra · Accepted Answer

Hello Student,Please find the answer to your question. KEY CONCEPT :eV = &frac12; mv 2p &shy; and eV = &frac12; mv2&prop;V is is the potential differenceVp = velocity of protonv&prop; = velocity of &prop; - particlem = mass of proton, mass of &prop; - particle = 4 m&rArr; vp = √ 2eV / m, v&prop; = √2eV / 4mNow when the particles enter in magnetic field, the force on proton isev p B = mv2p/ rp or rp = mvp / eB &rArr; r&prop;= m / eB√2eV / m = 1/B √ 2mV / e and r&prop; = 1/B √4mV /e&there4; rp / r&prop; = 1/ √2ThanksDeepak patraaskIITians Faculty

Magnetism> A proton and an α – particle are accelera...

A proton and an α – particle are accelerated with same potential difference and they enter in the region of constant magnetic field B perpendicular to the velocity of particles. Find the ratio of radius of curvature. Of proton to the radius of curvature of α – particle

Shane Macguire , 10 Years ago

Deepak Patra

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Magnetism> A proton and an α – particle are accelera...

A proton and an α – particle are accelerated with same potential difference and they enter in the region of constant magnetic field B perpendicular to the velocity of particles. Find the ratio of radius of curvature. Of proton to the radius of curvature of α – particle

Shane Macguire , 10 Years ago

Deepak Patra

Provide a better Answer & Earn Cool Goodies

LIVE ONLINE CLASSES

Ask a Doubt

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