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        A proton and a deuteron with same initial kinetic energy enter a magnetic field in a direction perpendicular to the direction of the field.the ratio of the radii of the circular trajectories described by them is
10 months ago

Vikas TU
11138 Points
							Hiii For Proton Let r(p) =x cm For deutron Let r(d)  = [2md(k)d]0.5/eB  = [4mp(k)p]0.50  = 1.41xFor alpha particles r(a) = [2ma(k)a]0.50/2eB = 2x cm So the ratio will be 1:sqrt2:2 or 1:1:sqrt2

10 months ago
Khimraj
3008 Points
							Radius of trajectory is given by , r= MV / BQSimilarly , V =$\sqrt{2vQ/M}$substitute and you will get ,r= sqrt ( 2MV / Q)B ………………….. (1)Here, V and B are constants … so we need to look into the mass and charge of each element.	Proton mass is 1 a.m.u and charge is +1e	For deutron , mass = 2 a.m.u	Alpha partical has mass 4 a.m.u and charge 2eSubstituting these values in (1) you get the ratios as 1 : sqrt(2) : sqrt (2)

9 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions