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# A particle of mass 0.5g and charge 3.5*10^-8 C is moving with velocity 6*10^4 m/s. What should be value of magnetic field acting on it so that particle moves in a straight line?

Eshan
3 years ago
Dear student,

If the magnetic field acts perpendicular to the directions of both velocity and acceleration due to gravity, the force due to it would balance the weight of particle.

Hence$\dpi{80} mg=qvB$

$\dpi{80} \implies B=\dfrac{mg}{qv}=2.38T$