A non-relativistic proton beam passes without deviation through the region of space where there are uniform transverse mutually perpendicular electric and magnetic fields- with E=120kV/m and B=50mT. Then the beam strikes a grounded target. Find the force with which the beam acts on the target if the beam current I=0.80mA
Kevin Nash , 11 Years ago
Grade upto college level
1 Answers
ROSHAN MUJEEB
Last Activity: 4 Years ago
Fe=Fm oreE=eBv ∴v=BE=50×10−3120×103=2.4×106m/s Let n be the number of protons striking per second.Then, ne=0.8×10−3 orn=1.6×10−190.8×10−3=5×1015/s Force imparted =rate of change of momentum =nmv =5×1015×1.67×10−27×2.4×106 =2.0×10−5N
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