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A metallic wire is folded to form a square loop of side 'a'. It carries a current 'i' and is kept perpendicular to a uniform magnetic field B. If the shape of the wire is changed from square to a circle without altering its length and the current, calculate the amount of work done in doing so.

Shane Macguire , 12 Years ago
Grade upto college level
anser 1 Answers
Askiitians Tutor Team

To find the work done in changing the shape of a metallic wire from a square loop to a circular loop while keeping the length and current constant, we need to consider the magnetic forces acting on the wire in both configurations. The work done can be calculated by comparing the magnetic potential energy in both shapes.

Understanding the Magnetic Force on the Wire

When a current-carrying wire is placed in a magnetic field, it experiences a magnetic force. The force \( F \) on a segment of wire can be described by the equation:

F = i (L × B)

where \( i \) is the current, \( L \) is the length vector of the wire segment, and \( B \) is the magnetic field vector. The direction of the force is given by the right-hand rule.

Calculating the Magnetic Force for Each Shape

First, let's calculate the magnetic force acting on the square loop. The total length of the wire is the perimeter of the square, which is:

Perimeter of square = 4a

For a square loop, the area \( A \) is:

A = a²

The magnetic moment \( \mu \) of the square loop is given by:

μ = i × A = i × a²

In a uniform magnetic field, the potential energy \( U \) associated with the magnetic moment is:

U = -μ · B = -i × a² × B

Transitioning to a Circular Loop

Now, when the wire is reshaped into a circular loop, the length of the wire remains the same, which is still \( 4a \). The circumference \( C \) of the circular loop is given by:

C = 2πr

Setting the circumference equal to the length of the wire, we have:

2πr = 4a

From this, we can solve for the radius \( r \):

r = \frac{2a}{π}

The area \( A \) of the circular loop is:

A = πr² = π\left(\frac{2a}{π}\right)² = \frac{4a²}{π}

The magnetic moment for the circular loop is then:

μ = i × A = i × \frac{4a²}{π}

Potential Energy of the Circular Loop

The potential energy for the circular loop in the magnetic field is:

U = -μ · B = -i × \frac{4a²}{π} × B

Calculating the Work Done

The work done \( W \) in changing the shape of the wire from a square loop to a circular loop is the difference in potential energy between the two configurations:

W = U_{circle} - U_{square}

Substituting the expressions we derived:

W = \left(-i × \frac{4a²}{π} × B\right) - \left(-i × a² × B\right)

Factoring out common terms:

W = -iB\left(\frac{4a²}{π} - a²\right)

Now, simplifying the expression gives:

W = -iB a² \left(\frac{4}{π} - 1\right)

Final Result

The work done in reshaping the wire from a square loop to a circular loop while maintaining the same length and current is:

W = -iB a² \left(\frac{4}{π} - 1\right)

This negative sign indicates that work is done against the magnetic field when changing the shape, which is an important consideration in electromagnetic applications. Understanding these principles helps in grasping the broader implications of magnetic fields on current-carrying conductors.

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