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\tA metal PQ of mass 10g lies at rest on two horizontal metal rails seperated by 4.90cm.A vertically downward magnetic feild of 0.800T exists in the space.the resistance of the circuit is slowly decreased and it is found that when the resistance goes below 20 omega,the wire PQ starts sliding on the rails.Find the coefficient of friction.

sankhadip das , 9 Years ago
Grade 12
anser 1 Answers
ROSHAN MUJEEB

Last Activity: 4 Years ago


Solution :
μR=FμR=F
rArrμ×m×g=iLBμ×m×g=iLB
μ×0.10×10−3×9.8μ×0.10×10-3×9.8
=620×4.9×10−2×0.8=620×4.9×10-2×0.8
μ=6×4.9×10−2×0.820×0.10×10−2×9.8μ=6×4.9×10-2×0.820×0.10×10-2×9.8
μ=0.12μ=0.12.

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