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a magnetism field of 2X10^3 Am-1 produces a magnetic flux density of 8 phi Tesla in an iron rod. the realative permeability of the rod will be
10^2
10^0
10^1
10^4

Pareena Yadav , 7 Years ago
Grade 12th pass
anser 1 Answers
Khimraj
relative permeability of rod is given by
ur = B/(uo*H)
H = 2*103 A/m
u0 = 4\pi*10-7
B = 8\pi
so,
ur = 104.
Hope it clears. If you like anser then please approve it.
Last Activity: 7 Years ago
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