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A long straight wire passes through the holes at the


opposite corners of a regular hexagon of side 10


cm.Calculate the magnetic field induction at the


point A,B,C and D due to small element of length 0.02


cm of the wire situated at the corner of the


hexagon .The current in the wire is 200 ampere.

Jitender Pal , 12 Years ago
Grade 9
anser 1 Answers
Askiitians Tutor Team

To find the magnetic field induction at points A, B, C, and D due to a small element of the wire, we can use the Biot-Savart Law. This law states that the magnetic field \( \mathbf{B} \) produced at a point in space by a small segment of current-carrying wire is directly proportional to the current flowing through the wire and inversely proportional to the square of the distance from the wire to the point where the field is being calculated. Let's break this down step by step.

Understanding the Setup

We have a regular hexagon with a side length of 10 cm. The wire passes through the corners of the hexagon, and we need to calculate the magnetic field at points A, B, C, and D, which are also at the corners of the hexagon. The current flowing through the wire is 200 A, and we will consider a small element of length 0.02 cm (or 0.0002 m) of the wire.

Applying the Biot-Savart Law

The Biot-Savart Law is given by the formula:

dB = (μ₀ / 4π) * (I * dl × r̂) / r²

Where:

  • dB = magnetic field due to the small element
  • μ₀ = permeability of free space (4π × 10⁻⁷ T·m/A)
  • I = current (200 A)
  • dl = length of the wire element (0.0002 m)
  • = unit vector from the wire element to the point of interest
  • r = distance from the wire element to the point of interest

Calculating the Distance and Unit Vector

For each point A, B, C, and D, we need to calculate the distance from the wire element to the point and the corresponding unit vector. The distance from the wire to each corner of the hexagon can be derived using the geometry of the hexagon.

For example, let's consider point A. The distance from the wire element at one corner to point A can be calculated using the Pythagorean theorem. Since the hexagon is regular, the distance from the center to any vertex is equal to the radius of the circumscribed circle, which is:

R = (side length) / (√3)

Thus, for a side length of 10 cm, R = 10 / √3 cm. The distance from the wire element to point A will be the hypotenuse of the triangle formed by the radius and the height of the hexagon.

Calculating Magnetic Field at Each Point

Once we have the distance \( r \) and the unit vector \( r̂ \) for each point, we can substitute these values into the Biot-Savart Law to find the magnetic field \( dB \) at each point. The direction of \( dB \) will be perpendicular to the plane formed by \( dl \) and \( r \), following the right-hand rule.

Example Calculation for Point A

Let’s say we find that the distance \( r \) from the wire element to point A is 0.1 m. The unit vector \( r̂ \) can be calculated based on the coordinates of the points. Substituting these values into the Biot-Savart Law:

dB_A = (4π × 10⁻⁷ / 4π) * (200 * 0.0002 × r̂_A) / (0.1)²

After calculating \( dB_A \), we can repeat this process for points B, C, and D, adjusting the distance and unit vector accordingly.

Summing the Contributions

Finally, since the magnetic fields at points A, B, C, and D are vector quantities, we need to sum the contributions from each segment of the wire to find the total magnetic field at each point. This involves adding the vector components of \( dB \) for each point.

By following these steps, you can calculate the magnetic field induction at points A, B, C, and D due to the small element of the wire. Each calculation will provide insight into how the geometry of the hexagon and the position of the wire influence the magnetic field at these points.

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