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A line charge lambda per unit length is lodgerd uniformly onto the rim of a wheel of mass 'M' radius 'R' . The wheel has non conducting spokes and is free to rotate without friction about axis. A uniform magnetic field extends over an a circular region of radius 'a' within rim. It is given by B= -B0 k (r<= a; a

what is the angular velocity of the wheel after the field is suddenly switched off?

Aditi Chauhan , 12 Years ago
Grade 10
anser 1 Answers
Askiitians Tutor Team

To determine the angular velocity of the wheel after the magnetic field is suddenly switched off, we need to analyze the situation using the principles of electromagnetism and rotational dynamics. The key here is to understand how the induced electromotive force (emf) affects the wheel's motion when the magnetic field changes.

Understanding the Setup

We have a wheel with a uniform line charge density, λ, distributed along its rim. The wheel is free to rotate about its axis and is subject to a uniform magnetic field, B, that exists within a circular region of radius 'a' (where 'a' is less than 'R', the radius of the wheel). The magnetic field is given by:

  • B = -B₀ k for r ≤ a
  • B = 0 for r > a

Induced EMF and Torque

When the magnetic field is suddenly switched off, the change in magnetic flux through the wheel induces an electromotive force (emf) around the rim. According to Faraday's law of electromagnetic induction, the induced emf (ε) can be calculated as:

ε = -dΦ/dt

Where Φ is the magnetic flux. The magnetic flux through the area of the wheel where the magnetic field is present can be expressed as:

Φ = ∫ B · dA

For our case, the area A is a circle of radius 'a', and the magnetic field is uniform. Thus, the flux can be simplified to:

Φ = B₀ * π * a²

Calculating the Change in Flux

When the magnetic field is switched off, the change in flux (dΦ) is equal to the initial flux since the final flux is zero:

dΦ = B₀ * π * a² - 0 = B₀ * π * a²

Assuming the switch-off happens instantaneously, we can consider the time interval dt to be very small, leading to a large induced emf:

ε = -dΦ/dt = -B₀ * π * a² / dt

Current and Torque on the Wheel

This induced emf will cause a current to flow around the rim of the wheel. The current (I) can be related to the induced emf by Ohm's law:

I = ε/R,

where R is the resistance of the rim. The torque (τ) acting on the wheel due to this current can be expressed as:

τ = I * r

Where 'r' is the radius of the wheel (R). Substituting for I gives:

τ = (ε/R) * R = ε

Angular Momentum and Angular Velocity

The angular momentum (L) of the wheel is related to its moment of inertia (I_wheel) and angular velocity (ω) by:

L = I_wheel * ω

When the magnetic field is switched off, the torque will cause a change in angular momentum:

τ = dL/dt

Assuming the torque acts for a very short time, we can integrate this to find the change in angular momentum:

ΔL = τ * Δt

Substituting τ gives:

ΔL = ε * Δt

Final Expression for Angular Velocity

Assuming the wheel starts from rest, the final angular momentum will be equal to the change in angular momentum:

I_wheel * ω = ε * Δt

Thus, the angular velocity after the field is switched off can be expressed as:

ω = (ε * Δt) / I_wheel

Conclusion

In summary, the angular velocity of the wheel after the magnetic field is suddenly switched off can be calculated using the induced emf from the change in magnetic flux, which leads to a torque that changes the angular momentum of the wheel. The exact value of ω will depend on the specific parameters of the system, including the resistance of the rim and the time duration of the switch-off.

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