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A hypothetical magnetic field existing in a region is given by B→= B0er→ Where er→ denotes the unit vector along the radial direction. A circular loop of radius a, carrying a current i , is placed with its plane parallel to X-Y plane and the centre at (0,0,d). Find the magnitude of the magnetic force acting on the loop.Sir, It is the Question Of H.C.Verma, Pg no.231 Volume2

Shane Macguire , 12 Years ago
Grade upto college level
anser 1 Answers
Askiitians Tutor Team

To find the magnetic force acting on a circular loop placed in a magnetic field, we can utilize the principles of electromagnetism, particularly the Lorentz force law. In this scenario, we have a magnetic field defined as **B** = B₀ **e**r, where **e**r is the unit vector in the radial direction, and a circular loop of radius 'a' carrying a current 'i' positioned parallel to the X-Y plane at the center (0,0,d).

Understanding the Magnetic Field and Loop Orientation

The magnetic field described is radial, which means it points outward from the origin in a spherical coordinate system. Since the loop is in the X-Y plane, we can visualize it as lying flat while the magnetic field varies with the radial distance from the origin.

Magnetic Force on a Current-Carrying Loop

The magnetic force **F** on a segment of wire carrying current **i** in a magnetic field **B** is given by the equation:

  • **F** = **i** (d**l** × **B**)

Here, d**l** is a differential length element of the loop. For a circular loop, we can express the total force by integrating around the loop.

Calculating the Force on the Loop

For a circular loop of radius 'a', the position of any point on the loop can be described in Cartesian coordinates as:

  • (a cos θ, a sin θ, d) for θ ranging from 0 to 2π.

The differential length element d**l** can be expressed as:

  • d**l** = (-a sin θ, a cos θ, 0) dθ

Next, we need to determine the magnetic field **B** at the location of the loop. Since the magnetic field is radial, at a distance 'r' from the origin, it can be expressed as:

  • **B** = B₀ **e**r = B₀ (cos φ **e**x + sin φ **e**y)

In our case, the angle φ can be derived from the geometry of the loop's position. The radial distance from the origin to the loop is:

  • r = √(a² + d²)

Thus, the magnetic field at the loop can be expressed as:

  • **B** = B₀ (a/√(a² + d²) **e**x + d/√(a² + d²) **e**y)

Cross Product Calculation

Now, we compute the cross product d**l** × **B**:

  • d**l** × **B** = (-a sin θ, a cos θ, 0) × B₀ (a/√(a² + d²) **e**x + d/√(a² + d²) **e**y)

Calculating this cross product will yield a vector that represents the force acting on each differential segment of the loop. After performing the calculations, we can integrate this force around the entire loop to find the total magnetic force.

Final Result

Upon integrating around the loop, we find that the net magnetic force acting on the loop is zero. This is due to the symmetry of the circular loop in the radial magnetic field, where the forces on opposite sides of the loop cancel each other out. Therefore, the magnitude of the magnetic force acting on the loop is:

  • F = 0

This result highlights an important principle in electromagnetism: while individual segments of the loop experience forces, the overall effect can lead to a net force of zero due to symmetry in certain configurations.

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