 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
a deutron of kinetic energy 50KeV is describing a circular orbit of radius 0.5m in a plane perpendicular to magnetic field B vector. the kinetic energy of the proton that describes a circular orbit of radius 0.5 metre in the same plane with the same Bvector is
a deutron of kinetic energy 50KeV is describing a circular orbit of radius 0.5m in  a plane perpendicular to magnetic field B vector. the kinetic energy of the proton that describes a circular orbit of radius 0.5 metre in the same plane with the same Bvector is

```
3 years ago

```							Kinetic energy of a charge particle moving in a magnetic field is given by..K=mv^2/r..&v=rqb/m..So,K=q^2r^2B^2/2m....we have K(d)=50keV...by taking the ratio of K(p) to K(d),we get.....K(p)/K(d)=[q(p)]^2 r^2B^2/2m(p)×2m(d)/q(d)^2
```
3 years ago
```							Kinetic energy of a charge particle moving in a magnetic field is given by K=q^2r^2B^2/2m...K(p)/K(d)=[q(p)]^2r^2B^2/2m(p)×2m(d)/[q(d)]^2r^2B^2.......q(d)=q(p)...m(d)=2m(p)...By putting value,K(p)=2K(d)...K(p)=100keV
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Magnetism

View all Questions »  ### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions