A cylindrical wire (hollow) has internal radius =R, thickness =0. Let there be a point P (a) outside of the cylinder (b) inside of the cylinder at a distance r. Find the magnetic flux inside and outside.

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Vikas TU · Answer

Hiii In a hollow cyllinder of thickness almost equal to zero , The magnetic field strength inside the hollow cyllinder = o Outside the surface of hollow cyllinder Apply Ampere circuital law , and find you will get it as B = (mew *I)/2*Pi*r

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A cylindrical wire (hollow) has internal radius =R, thickness =0. Let there be a point P (a) outside of the cylinder (b) inside of the cylinder at a distance r. Find the magnetic flux inside and outside.

A cylindrical wire (hollow) has internal radius =R, thickness =0. Let there be a point P (a) outside of the cylinder (b) inside of the cylinder at a distance r. Find the magnetic flux inside and outside.

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A cylindrical wire (hollow) has internal radius =R, thickness =0. Let there be a point P (a) outside of the cylinder (b) inside of the cylinder at a distance r. Find the magnetic flux inside and outside.

A cylindrical wire (hollow) has internal radius =R, thickness =0. Let there be a point P (a) outside of the cylinder (b) inside of the cylinder at a distance r. Find the magnetic flux inside and outside.

1 Answers

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Other Related Questions on Magnetism

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