A cyclotron is used to obtain 2 MeV protons. If the frequency is 5MHz and potential is 20KV. The magnetic field necessary for resonance is

Question

Umakant biswal · Answer

@ sridhar
u can use the following formula to get the right answer .,
f = bq / 2m pie
no need of potential and proton energy .
by solving u will get
2vmev = ½ m v square
u will get v from their
20 kv = v / 4 pie efsilon not r
HOPE IT CLEARS

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A cyclotron is used to obtain 2 MeV protons. If the frequency is 5MHz and potential is 20KV. The magnetic field necessary for resonance is

A cyclotron is used to obtain 2 MeV protons. If the frequency is 5MHz and potential is 20KV. The magnetic field necessary for resonance is

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