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A cyclotron is used to obtain 2 MeV protons. If the frequency is 5MHz and potential is 20KV. The magnetic field necessary for resonance is A cyclotron is used to obtain 2 MeV protons. If the frequency is 5MHz and potential is 20KV. The magnetic field necessary for resonance is
@ sridhar u can use the following formula to get the right answer ., f = bq / 2m pie no need of potential and proton energy . by solving u will get 2vmev = ½ m v square u will get v from their 20 kv = v / 4 pie efsilon not r HOPE IT CLEARS ALL THE BEST ..
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