A current through galvanometer #Ig# is 2mA give full scale deflection with #Rg# 15ohms the amount of shunt connected to it to convert it into 10A ammeter is a) 0.030 b) 3 c) 5?
Rabik John , 7 Years ago
Grade 12th pass
1 Answers
ashish
Last Activity: 7 Years ago
dear rabik as Ig *Rg =(I-Ig)S (S = SHUNT) 2*10-3 *15= (10-2*10-3) S 30*10-3 =10S (10-2*10-3 =10 approx) 3*10-3ohm =S Ans