A current through galvanometer #Ig# is 2mA give full scale deflection with #Rg# 15ohms the amount of shunt connected to it to convert it into 10A ammeter is a) 0.030 b) 3 c) 5?

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ashish · Answer

dear rabik as Ig *Rg =(I-Ig)S (S = SHUNT) 2*10-3 *15= (10-2*10-3) S 30*10-3 =10S (10-2*10-3 =10 approx) 3*10-3ohm =S Ans

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A current through galvanometer #Ig# is 2mA give full scale deflection with #Rg# 15ohms the amount of shunt connected to it to convert it into 10A ammeter is a) 0.030 b) 3 c) 5?

A current through galvanometer #Ig# is 2mA give full scale deflection with #Rg# 15ohms the amount of shunt connected to it to convert it into 10A ammeter is a) 0.030 b) 3 c) 5?

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A current through galvanometer #Ig# is 2mA give full scale deflection with #Rg# 15ohms the amount of shunt connected to it to convert it into 10A ammeter is a) 0.030 b) 3 c) 5?

A current through galvanometer #Ig# is 2mA give full scale deflection with #Rg# 15ohms the amount of shunt connected to it to convert it into 10A ammeter is a) 0.030 b) 3 c) 5?

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