Flag Magnetism> A current carrying coil is placed with it...
question mark

A current carrying coil is placed with its axis parallel to N-S direction. Let horizontal component of earth's magnetic field be div and magnetic field inside the loop is H. If a magnet is suspended inside the loop, it makes angle L with H. Then L =

(a) tan inverse (div/H)
(b) tan inverse (H/div)

Hrishant Goswami , 11 Years ago
Grade 10
anser 1 Answers
Askiitians Tutor Team

Last Activity: 4 Months ago

To tackle this question, we need to analyze the situation involving a current-carrying coil and the magnetic fields at play. When a magnet is suspended inside the coil, it experiences the magnetic field produced by the coil itself and the horizontal component of the Earth's magnetic field. The angle L that the magnet makes with the magnetic field inside the loop can be determined using the relationship between these magnetic fields.

Understanding the Magnetic Fields

In this scenario, we have two magnetic fields to consider:

  • H1: The horizontal component of the Earth's magnetic field.
  • H: The magnetic field inside the coil due to the current flowing through it.

Analyzing the Forces

When the magnet is suspended inside the coil, it aligns itself with the resultant magnetic field, which is the vector sum of H and H1. The angle L that the magnet makes with the magnetic field inside the loop can be understood through the tangent of that angle, which relates the two magnetic fields.

Using Trigonometry

In a right triangle formed by the two magnetic fields, we can express the tangent of angle L as:

tan(L) = Opposite / Adjacent

In this case, the opposite side corresponds to the horizontal component of the Earth's magnetic field (H1), and the adjacent side corresponds to the magnetic field inside the loop (H). Therefore, we can write:

tan(L) = H1 / H

Finding the Correct Expression

To find L, we take the inverse tangent (or arctangent) of both sides:

L = tan inverse(H1 / H)

However, we need to express this in terms of the given options. Since we are looking for the angle L in terms of H1 and H, we can rearrange our expression:

tan(L) = H1 / H implies that:

L = tan inverse(H1 / H)

Conclusion

Given the options provided in your question, the correct answer is not explicitly listed. However, if we consider the relationship between H and H1, we can deduce that:

If we were to express L in terms of H and H1, we would find:

L = tan inverse(H / H1) when rearranging the relationship. Thus, the correct choice from the options given is:

(b) tan inverse(H / H1)

In summary, the angle L that the magnet makes with the magnetic field inside the loop is determined by the ratio of the magnetic fields, and the correct expression is indeed (b) tan inverse(H / H1).

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments