A conducting rod is placed in East West direction and move in East West direction then how much induced emf is produced.

B is the magneetic field and X is the angle of dip 

    then horizontal magnetic field is BcosX

    length of rod is L

    velocity of the rod falling is (2gH)^½ 

      induced emf is = Blv = Bcosx.L.(2gH)^1/2

You can find the direction of the emf using Fleming's right hand rule, assuming the magnetic field lines are from south to north ( since the magnetic north pole lies near geographic south pole) the current in the rod will be from west to the east. So the east side will will positive.

However the magnitude calculation is a little more difficult. The free fall of the rod under is an accelerated motion and the field is also non uniform if the height is high enough.