Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A conducting rod is placed in East West direction and move in East West direction then how much induced emf is produced.

A conducting rod is placed in East West direction and move in East West direction then how much induced emf is produced.

Grade:12th pass

2 Answers

Arun
25763 Points
one year ago
 
B is the magneetic field and X is the angle of dip 
    then horizontal magnetic field is BcosX
    length of rod is L
    velocity of the rod falling is (2gH)½ 
      induced emf is = Blv = Bcosx.L.(2gH)1/2
Vikas TU
14149 Points
one year ago
Der student 
You can find the direction of the emf using Fleming's right hand rule, assuming the magnetic field lines are from south to north ( since the magnetic north pole lies near geographic south pole) the current in the rod will be from west to the east. So the east side will will positive.
However the magnitude calculation is a little more difficult. The free fall of the rod under is an accelerated motion and the field is also non uniform if the height is high enough.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free