Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A circular loop of radius 1m is kept in a magnetic field of strength 2T (plane of loop is perpendicular to the direction of magnetic field).Resistance of the loop wire is . A conductor of length 2m in sliding with a speed 1m/s as shown in the figure. Find the instantaneous force acting on the rod:[Assume rod has negligible resistance]...............?


A circular loop of radius 1m is kept in a magnetic field of strength 2T (plane of loop is perpendicular to the direction of magnetic field).Resistance of the loop wire is       . A conductor of length 2m in sliding with a speed 1m/s as shown in the figure. Find the instantaneous force acting on the rod:[Assume rod has negligible resistance]...............?


Grade:10

1 Answers

ROSHAN MUJEEB
askIITians Faculty 829 Points
one year ago
let induced emf is (e) = V B lwhere V = velocity of conductor , B = magnetic field intensity , l = length of conductor.
Current is I.If resistance of loop is 2 R then circuit will be .
currentI=R1​∥R2​e​
=12e​=2VBl
ForceFm​=ilB=2vB2l2=2×1×22×2Fm​=16N

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free