A circular loop of radius 1m is kept in a magnetic field of strength 2T (plane of loop is perpendicular to the direction of magnetic field).Resistance of the loop wire is . A conductor of length 2m in sliding with a speed 1m/s as shown in the figure. Find the instantaneous force acting on the rod:[Assume rod has negligible resistance]...............?

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ROSHAN MUJEEB · Answer

let induced emf is (e) = V B lwhere V = velocity of conductor , B = magnetic field intensity , l = length of conductor.
Current is I.If resistance of loop is 2 R then circuit will be .
currentI=R1∥R2e
=12e=2VBl
ForceFm=ilB=2vB2l2=2×1×22×2Fm=16N

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