Flag Magnetism> A circular coil of radius 8 cm and having...
question mark

A circular coil of radius 8 cm and having 49 turns of a wire is placed such that the plane of the coil co insides with the magnetic meridian in the place . A compass needle is kept at the centre of the coil, such that its needle can rotate freely in the horizontal plane . if the horizontal intensity of the earth's magnetic field in the horizontal plane . If the horizontal intensity of the earth's magnetic field is 22.48*10^-6 T and if 0.8A current flows through the coil , calculate the deflecti

Amit Saxena , 12 Years ago
Grade upto college level
anser 1 Answers
Askiitians Tutor Team

To determine the deflection of the compass needle placed at the center of a circular coil, we can use the principles of electromagnetism. The coil generates a magnetic field when an electric current flows through it, and this magnetic field interacts with the Earth's magnetic field, causing the compass needle to deflect. Let's break down the calculation step by step.

Understanding the Magnetic Field of the Coil

The magnetic field (B) at the center of a circular coil can be calculated using the formula:

B = (μ₀ * n * I) / 2

Where:

  • B = magnetic field at the center of the coil (in teslas)
  • μ₀ = permeability of free space (4π × 10-7 T·m/A)
  • n = number of turns per unit length (in turns/m)
  • I = current flowing through the coil (in amperes)

Calculating the Number of Turns per Unit Length

Since we have a circular coil with 49 turns, we can express the number of turns per unit length as:

n = Total turns / Length of the coil

The length of the coil can be calculated using the circumference formula:

Length = 2πr

Given that the radius (r) is 8 cm (which is 0.08 m), we can calculate:

Length = 2π(0.08) ≈ 0.5027 m

Now we can find n:

n = 49 turns / 0.5027 m ≈ 97.4 turns/m

Calculating the Magnetic Field at the Center of the Coil

Now we can substitute the values into the magnetic field formula:

B = (4π × 10-7 T·m/A * 97.4 turns/m * 0.8 A) / 2

Calculating this gives:

B ≈ (4π × 10-7 * 97.4 * 0.8) / 2 ≈ 4.9 × 10-5 T

Finding the Deflection of the Compass Needle

The deflection (θ) of the compass needle can be found using the tangent of the angle, which relates the magnetic field of the coil to the Earth's magnetic field:

tan(θ) = B / Bearth

Where:

  • B = magnetic field due to the coil (4.9 × 10-5 T)
  • Bearth = horizontal intensity of the Earth's magnetic field (22.48 × 10-6 T)

Substituting the values:

tan(θ) = (4.9 × 10-5) / (22.48 × 10-6)

Calculating this gives:

tan(θ) ≈ 2.18

Calculating the Angle of Deflection

To find the angle θ, we take the arctangent:

θ = arctan(2.18)

Using a calculator, we find:

θ ≈ 65.4°

Summary of Results

The compass needle will deflect approximately 65.4 degrees due to the magnetic field generated by the current flowing through the coil. This interaction between the coil's magnetic field and the Earth's magnetic field illustrates the principles of electromagnetism and how electric currents can create magnetic effects.

ApprovedApproved
Last Activity: 8 Months ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments