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A Charged Particle is made to travel inside a magnetic field...It is fired with a

velocity of v AT PERPENDICULAR direction to the magnetic field..Choose the

correct option----------

a)MOMENTUM and KINETIC ENERGY changes

b)MOMENTUM changes but KINETIC ENERGY remains constant

c)MOMENTUM remains same but KINETIC ENERGY changes

d)NEITHER CHANGES.......................

Shane Macguire , 11 Years ago
Grade upto college level
anser 1 Answers
Biswajit Das

Last Activity: 10 Years ago

Option (d) is correct. The magnitude of the velocity and mass of the particle will be constant under all conditions. So, momentum remains same. As the magnitude of the velocity of the particle is constant, therefore K.E (= ½ mv2) is also a constant quantity. Thus from the above observation, we conclude that, option (d) is correct.

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