A beam of protons with a velocity 4 x 105 m/sec enters a

Question

A beam of protons with a velocity 4 x 105m/sec enters a uniform magnetic field of 0.3 tesla at an angle of 60oto the magnetic field.Find the radius of the helical path taken by the proton beam. Also find the pitch of the helix (which is the distance travelled by a proton in the beam parallel to the magnetic field during one period of rotation).ans:radius =0.012mpitch=0.044m

ROSHAN MUJEEB · Accepted Answer

dear student,The radius of helical path:r=Bqmv&perp;​​=Bqmvsinθ​=(0.3)(1.6&times;10&minus;19)(1.67&times;10&minus;27)(4&times;105)(sin60o)​=1.2&times;10&minus;2mPitch of helical path,p=v∥​&times;TP=(Bq2&pi;m​)(vcosθ) =(03.)(1.6&times;10&minus;19)(2&pi;)(1.67&times;10&minus;27)(4&times;105)(cos60o)​=4.37&times;10&minus;2mhope it helps

Magnetism> A beam of protons with a velocity 4 x 105...

Aditi Chauhan , 11 Years ago

ROSHAN MUJEEB

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Magnetism> A beam of protons with a velocity 4 x 105...

Aditi Chauhan , 11 Years ago

ROSHAN MUJEEB

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