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A bar magnetof lengtdiv0 cm and pole strength 20 A-m is deflected through30 degrees from the magnetic meridian.If earth's horizontal component of field is 320/4pie A/m.The moment of the deflecting couple is

Lubna , 6 Years ago
Grade 12
anser 1 Answers
ROSHAN MUJEEB

Last Activity: 4 Years ago


It is given that length of bar magnet L=10cm=0.1m
Pole strength m=20A−m
earths horizontal component field B
H

=

320

Am
−1

torqueτ=MBsinθ
τ=mlBsinθ
τ=20×0.1×

320

×sin30
τ=25.4Nm

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