A bar magnetof length10 cm and pole strength 20 A-m is deflected through30 degrees from the magnetic meridian.If earth's horizontal component of field is 320/4pie A/m.The moment of the deflecting couple is

Question

ROSHAN MUJEEB · Answer

It is given that length of bar magnet L=10cm=0.1m
Pole strength m=20A−m
earths horizontal component field B
H

=
4π
320

Am
−1

torqueτ=MBsinθ
τ=mlBsinθ
τ=20×0.1×
4π
320

×sin30
τ=25.4Nm

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A bar magnetof length10 cm and pole strength 20 A-m is deflected through30 degrees from the magnetic meridian.If earth's horizontal component of field is 320/4pie A/m.The moment of the deflecting couple is

A bar magnetof length10 cm and pole strength 20 A-m is deflected through30 degrees from the magnetic meridian.If earth's horizontal component of field is 320/4pie A/m.The moment of the deflecting couple is

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A bar magnetof length10 cm and pole strength 20 A-m is deflected through30 degrees from the magnetic meridian.If earth's horizontal component of field is 320/4pie A/m.The moment of the deflecting couple is

A bar magnetof length10 cm and pole strength 20 A-m is deflected through30 degrees from the magnetic meridian.If earth's horizontal component of field is 320/4pie A/m.The moment of the deflecting couple is

1 Answers

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