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Grade 11Magnetism

a bar magnet of length 3cm has points A and B along its axis at distances of 24cm and 48cm on the opposite sides. how to calculate the ratio of magnetic field at these points ?

Profile image of Urvashi Kaul
9 Years agoGrade 11
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2 Answers

Profile image of Anu
8 Years ago
B is inversely proportional to one upon (distance)3 this you see in on axial and normal bisector (magnetic field due to bar magnet)Now, Ba/Bb=(48/24)3 =8/1 answer
Profile image of ankit singh
5 Years ago
Length of magnet = 3 cm
Distance between point a and center of magnet= 24 cm
Distance between point b and center of magnet= 48 cm
The magnetic field is
B=\dfrac{\mu_{0}\times 2m}{4\pi\times d^3}
B\propto\dfrac{1}{d^3}
The magnetic field is inversely proportional to the cube of the distance.
We need to calculate the ratio of magnetic fields at these points
Using formula of magnetic field
\dfrac{B_{a}}{B_{b}}=\dfrac{d_{b}^3}{d_{a}^2}
\dfrac{B_{a}}{B_{b}}=\dfrac{48^3}{24^3}
\dfrac{B_{a}}{B_{b}}=\dfrac{8}{1}
 

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