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a bar magnet of length 3cm has points A and B along its axis at distances of 24cm and 48cm on the opposite sides. how to calculate the ratio of magnetic field at these points ?


4 years ago

Anu
11 Points
							B is inversely proportional to one upon (distance)3 this you see in on axial and normal bisector (magnetic field due to bar magnet)Now, Ba/Bb=(48/24)3          =8/1 answer

3 years ago
ankit singh
596 Points
							Length of magnet = 3 cmDistance between point a and center of magnet= 24 cmDistance between point b and center of magnet= 48 cmThe magnetic field isB=\dfrac{\mu_{0}\times 2m}{4\pi\times d^3}B\propto\dfrac{1}{d^3}The magnetic field is inversely proportional to the cube of the distance.We need to calculate the ratio of magnetic fields at these pointsUsing formula of magnetic field\dfrac{B_{a}}{B_{b}}=\dfrac{d_{b}^3}{d_{a}^2}\dfrac{B_{a}}{B_{b}}=\dfrac{48^3}{24^3}\dfrac{B_{a}}{B_{b}}=\dfrac{8}{1}

4 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions