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a bar magnet of geometric length 18cm has pole strength 100 A.m. Find magnetic dipole moment of bar magnet
geometric length = 18cmpole strength (m) = 100M = ?as magnetic length(2l) = 5\6 geometric lengthmagnetic length(2l) = 5\6 . 15 = 15cm so that 2l = 0.15mnow M = m.2l = 100. 0.15 = 15 Am2
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