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A a straight horizontal bar of mass 10 mg and length 1m carries a current of 2 ampere what minimum magnetic field should be applied in the region so that the magnetic force on the wire may balance it's weight

Ayush Tiwari , 7 Years ago
Grade
anser 1 Answers
Susmita
Magnetic force on the wire F=IBL=2*B*1=2B
Weight=mg=10×10-3×10=0.1
F=0.1
Or,B=0.1/2=0.05T=50 mT
If it helps please approve.
 
Last Activity: 7 Years ago
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