A a straight horizontal bar of mass 10 mg and length 1m carries a current of 2 ampere what minimum magnetic field should be applied in the region so that the magnetic force on the wire may balance it's weight

Question

Susmita · Answer

Magnetic force on the wire F=IBL=2*B*1=2B Weight=mg=10×10 -3 ×10=0.1 F=0.1 Or,B=0.1/2=0.05T=50 mT If it helps please approve.

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A a straight horizontal bar of mass 10 mg and length 1m carries a current of 2 ampere what minimum magnetic field should be applied in the region so that the magnetic force on the wire may balance it's weight

A a straight horizontal bar of mass 10 mg and length 1m carries a current of 2 ampere what minimum magnetic field should be applied in the region so that the magnetic force on the wire may balance it's weight

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A a straight horizontal bar of mass 10 mg and length 1m carries a current of 2 ampere what minimum magnetic field should be applied in the region so that the magnetic force on the wire may balance it's weight

A a straight horizontal bar of mass 10 mg and length 1m carries a current of 2 ampere what minimum magnetic field should be applied in the region so that the magnetic force on the wire may balance it's weight

1 Answers

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