Guest

A bar magnet of length 'l' and having pole strength 'm' is placed vertically on a horizontal tablewith its south pole on the table. A neutral point is found on the table at a distance 'x' north of the magnet. calculate the horizontal component of earth's magnetic field.

A bar magnet of length 'l' and having pole strength 'm' is placed vertically on a horizontal tablewith its south pole on the table. A neutral point is found on the table at a distance 'x' north of the magnet. calculate the horizontal component of earth's magnetic field.

Grade:12

1 Answers

ROSHAN MUJEEB
askIITians Faculty 829 Points
2 years ago
magnetic field due to pole of strengthmat distancedis
B=4πd2μ0​m​Vertical component of earth's magnetic field =0.4×10−4Wbm−2
At the neutral point,4πd2μ0​m​=0.4×10−4
⟹m=16A−m

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free