A bar magnet of length 'l' and having pole strength 'm' is placed vertically on a horizontal tablewith its south pole on the table. A neutral point is found on the table at a distance 'x' north of the magnet. calculate the horizontal component of earth's magnetic field.

Question

ROSHAN MUJEEB · Answer

magnetic field due to pole of strengthmat distancedis
B=4πd2μ0mVertical component of earth's magnetic field =0.4×10−4Wbm−2
At the neutral point,4πd2μ0m=0.4×10−4
⟹m=16A−m

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A bar magnet of length 'l' and having pole strength 'm' is placed vertically on a horizontal tablewith its south pole on the table. A neutral point is found on the table at a distance 'x' north of the magnet. calculate the horizontal component of earth's magnetic field.

A bar magnet of length 'l' and having pole strength 'm' is placed vertically on a horizontal tablewith its south pole on the table. A neutral point is found on the table at a distance 'x' north of the magnet. calculate the horizontal component of earth's magnetic field.

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A bar magnet of length 'l' and having pole strength 'm' is placed vertically on a horizontal tablewith its south pole on the table. A neutral point is found on the table at a distance 'x' north of the magnet. calculate the horizontal component of earth's magnetic field.

A bar magnet of length 'l' and having pole strength 'm' is placed vertically on a horizontal tablewith its south pole on the table. A neutral point is found on the table at a distance 'x' north of the magnet. calculate the horizontal component of earth's magnetic field.

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