Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
An insulating rod of length l carries a charge q distributed uniformly on it.The rod is pivoted at an end and is rotated at a frequency f about a fixed perpendicular axis.The magnetic moment of the system is? An insulating rod of length l carries a charge q distributed uniformly on it.The rod is pivoted at an end and is rotated at a frequency f about a fixed perpendicular axis.The magnetic moment of the system is?
let the charge density on rod be λ = q/l consider a small element of rod dx at a distance x from the fixed end charge on it dq = λ dx when the rod rotates the current due to this element , di = f dq = f λ dx magnetic moment of this current element dM = di * area = f λ dx * ∏ x^2 total magnetic moment M = ∫ dM = = ∫0 l f λ dx * ∏ x^2 = fλ∏ ∫0 l ( x^2 ) dx = fλ∏/3 * x^3 ]0 l = fλ∏ l^3 /3 λ l = q , so M = f∏q l^2 /3
let the charge density on rod be λ = q/l
consider a small element of rod dx at a distance x from the fixed end
charge on it dq = λ dx
when the rod rotates the current due to this element , di = f dq
= f λ dx
magnetic moment of this current element dM = di * area
= f λ dx * ∏ x^2
total magnetic moment M = ∫ dM =
= ∫0 l f λ dx * ∏ x^2
= fλ∏ ∫0 l ( x^2 ) dx
= fλ∏/3 * x^3 ]0 l
= fλ∏ l^3 /3
λ l = q , so
M = f∏q l^2 /3
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -