MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        A square coil of edge l having n turns carries a current i. It is kept on a smooth horizontal plate. A ujiform magnetic field B exists in a direction parrallel to an edge. The total mass of the coil is M. What should be the minimum value of B for which the coil will start tipping over? What is meant by tipping over?
10 years ago

Answers : (2)

umesh chandrakant shah
36 Points
							

can anybody help me solving my problem?

thanks.

10 years ago
vikash chandola
21 Points
							

hello umesh

magnetic field will apply force on only those sides where current is perpendicular to the sides so force will only act on 2 sides of the square

by knowledge of rotational motin find out the torque acting on the sides of the square about which magnetic field is not parlell now consider the rest state of coil now find out the torque applied by earth's  gravitational field.

when the torque due to the magnetic field and gravitational field became equal coil will start tipping.

if you like the answer please approve it

 

9 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details