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a particle of mass m, accelerated by a potential differece V flies through a uniform transverse magnetic field B. The magnetic field is spread in the thickness d. calculate the angle through which particle will deviate from the initial direction of motion.
hi , velocity of particle v = ( 2*q*V/m) 1/2 & radius of path , r = m*v /q*B if d > r than particl will cover one half circle & will leave at 180 angle deviated from initial if d= r than particl will cover one fourth of circle & will leave at 90 angle deviated from initial if d < r than it will deviat an angle of sin^ -1 (d/r) v
hi ,
velocity of particle v = ( 2*q*V/m) 1/2
& radius of path , r = m*v /q*B
if d > r
than particl will cover one half circle & will leave at 180 angle deviated from initial
if d= r
than particl will cover one fourth of circle & will leave at 90 angle deviated from initial
if d < r
than it will deviat an angle of sin^ -1 (d/r)
v
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