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plz help a circular current carrying coil has radius r. Then distance from which centre of coil on the axis when the magnetic inductions will be 1/8 of its value at centre of coil is...?

plz help
a circular current carrying coil has radius r. Then distance from which centre of coil on the axis when the magnetic inductions will be 1/8 of its value at centre of coil is...?

Grade:12

2 Answers

vikas askiitian expert
509 Points
11 years ago

B(axis) = uoIr2/2(r2+x2)3/2

B(center) = uoI/2r

 

B(axis) = 1/8 (B(center) so

r2/(r2+x2)3/2 = 1/8r

8r3 = (r2+x2)3/2

(2r)2  =  r2 + x2

 x = r(root3)

 

approve if u like my ans

Kushagra Madhukar
askIITians Faculty 629 Points
2 years ago
Dear student,
Please find the attached solution to your problem
B(axis) = uoIr2/2(r2+x2)3/2
B(center) = uoI/2r
B(axis) = 1/8 * B(center)
so
r2/(r2+x2)3/2 = 1/8r
8r3 = (r2+x2)3/2
(2r)2 = r2 + x2
x = r√3
Thanks and regards,
Kushagra

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