badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

                        

Dear sir, Please explain the concept of magnetic moment in detail and there is a sum based on it please explain how to solve it. The sum is, An insulating rod of length l carries uniform charge q distributed on it. It is pivoted at middle point and rotated with frequency f about a fixed axis perpendicular to the rod and passing through the pivot so what is the magnetic moment of the system?

9 years ago

Answers : (1)

vikas askiitian expert
509 Points
							

first read this carefully

 

consider a charge moving in a circular path ...let radius of its path of radius r ...

due to its motion it a current is produced along the path ...then motion this particle

can be compared to a charged ring of radius r, circulating with some angular velocity...

 

magnetic moment = M = IA = I(pir2)               .........................1


 

we have to calculate magnetic moment for rod , let mid point of rod is O ...

now  consider two small elements dq of thickness dx on the rod which are at distance x from center

on both sides...

this (dq+dq) charge is moving in circle so producing current ...

total charge= 2dq

charge per unit length = q/L

dq = (q/L)dx  so

total charge = (2q/L)dx                     .........................2

total current over 1 complete revolution (t = 2pi/w) = total charge/t = (wq/piL)dx    .......3            (w = angular frequency)

area of circle  = pix2 so

magnetic moment = (total current)(area)

                          =pix2(wq/piL)dx

                    dM = (wq/L)x2dx

integrating both sides

          M = (wq/L) (x3/3)             lim 0 to L/2

          M = (wq/L)(L2/24)

          M = wqL2/24   

now , w = 2pif so

        M = piqL2/12

this is the required result

 

9 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details