Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
first read this carefully
consider a charge moving in a circular path ...let radius of its path of radius r ...
due to its motion it a current is produced along the path ...then motion this particle
can be compared to a charged ring of radius r, circulating with some angular velocity...
magnetic moment = M = IA = I(pir2) .........................1
we have to calculate magnetic moment for rod , let mid point of rod is O ...
now consider two small elements dq of thickness dx on the rod which are at distance x from center
on both sides...
this (dq+dq) charge is moving in circle so producing current ...
total charge= 2dq
charge per unit length = q/L
dq = (q/L)dx so
total charge = (2q/L)dx .........................2
total current over 1 complete revolution (t = 2pi/w) = total charge/t = (wq/piL)dx .......3 (w = angular frequency)
area of circle = pix2 so
magnetic moment = (total current)(area)
=pix2(wq/piL)dx
dM = (wq/L)x2dx
integrating both sides
M = (wq/L) (x3/3) lim 0 to L/2
M = (wq/L)(L2/24)
M = wqL2/24
now , w = 2pif so
M = piqL2/12
this is the required result
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !