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A long thin walled pipe of radius R carries current I along its length.The current density is uniform over circumference of pipe.The magnetic field at the centre of pipe due to quarter portion of pipe?-Please answer and explain.....
total current through circumfrence = I
current through unit segment of circumfrenece = I/2piR (current dencity)
length of quater of segment = 2piR/4 = piR/2
current through quater segment (piR/2)= (I/2piR)(piR/2)
=I/4
now we have , B.dl = uoI(current threading)
B(2PiR) = uo(I/4)
B = uoI/8piR
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