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Grade:Upto college level

1 Answers

Rathod Shankar AskiitiansExpert-IITB
69 Points
11 years ago

 

 

 

 

this id for perpendicular to magnetic filed  for some angle    force F = qvBsinΦ     heree     Φ=90-θ

 

F=qvBcosθ =mv2 /r

qBcosθ= mv/r

 

r= qBcosθ/mV

 

 

 

for negative charge the force is opposite F. solve that for practice.

 

 

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