Grade:Upto college level

1 Answers

Rathod Shankar AskiitiansExpert-IITB
69 Points
12 years ago





this id for perpendicular to magnetic filed  for some angle    force F = qvBsinΦ     heree     Φ=90-θ


F=qvBcosθ =mv2 /r

qBcosθ= mv/r


r= qBcosθ/mV




for negative charge the force is opposite F. solve that for practice.



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