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# what is the formulae for (a+b)3  and derive expression

N JYOTHEESWAR
342 Points
5 years ago
the formulae for (a+b)3 is a+3a2b+3ab2+b3. if we derive this we get the expansion like this.this the formulae .

vannala shivanand
23 Points
5 years ago
The formula of (a+b)3 is a3 +b3 +3a2b+3ab2 . if we multiply (a+b) terms three times itself then we can get formula.or we can get the formula by using binomial theroem.

317 Points
5 years ago
the formula for (a+b)3
=a3+b3+3a2b+3ab2 this is formula of (a+b)^3. this formula is very useful while solving formulas

NARAYANA
242 Points
5 years ago
THE FORMULA FOR (a+b)^3 is a^3+b^3+3a^2b+3ab^2 we get this we multify (a+b)(a+b)(a+b) then we get the answer.
SAI SARDAR
1700 Points
5 years ago
Dear Prabhakar,
The formula for (a+b)3 is a3 + b3 + 3a2b + 3ab2 .It is derived from using binomial thereom.
Dheeru chowdary
100 Points
5 years ago
The expansion for that algebraic formula is ^3 +b^3 +3ba^2 +3ab^2    . & after the derivation u will get the same expansion
,

,
,                ,        ..mr.ch prabhakar
T.kumar
281 Points
5 years ago

The expansion for that algebraic formula is ^3 +b^3 +3ba^2 +3ab^2    . & after the derivation u will get the same expansion
,
RAMCHANDRARAO
159 Points
5 years ago
the formulae for (a+b)3 is a3+b3+3a2b+3ab2
in (a+b)3 you have to write (a+b)*(a+b)*(a+b) if you multiply the these three you can get the formulae
Gowri sankar
292 Points
5 years ago
DEAR PRABHAKAR, The formula of (a+b)^2
subramanyam
53 Points
5 years ago
. if we derive this we get the expansion like this.this the formulae .3+b2b+3ab2+3a is a3The formulae for (a+b)
mohan
216 Points
5 years ago
dear prabhakar..................................................................................
the formula of [a+b]^3 is a3+3b2b+3ab2+b3

NAGOORVALI
105 Points
5 years ago
dear prabhakar formulea for (a+b)^3=a^3+b^3+3ab^2+3a^2b .......................................................
sreekanth sree
125 Points
5 years ago
hello prabhakar answer this question is
1. 3+b3+3a2b+3ab2.   thank you for asking a question.all tyhe best for your bright future.
raj
384 Points
5 years ago
HELLO PRABHAKAR
the formulae for (a+b)3 is a3+b3+3a2b+3ab2
in (a+b)3 you have to write (a+b)*(a+b)*(a+b) if you multiply the these three you can get the formulae
131 Points
5 years ago
hello prabhakar
the  formula  of  (a+b)3  =a2+b2+3a2b+3ab2….….….….….….….…..
and it is a one of the binomial  expansion.
NAVEENKUMAR NAGIPOGU
108 Points
5 years ago
my dear prabhakar
the formula for  =3(a+b)2 my dear prabhakar i hope you are understand.b+3ab2+3a3+b3a
Forum Team
94 Points
5 years ago
This is to inform all forum users who are posting questions and then approving answers of all the users in same question just to give points to their friends so that they can get the gift vouchers. This is against the forum policy and users will not get benefit of these approval points. They will get benefit of posting answers only and that too which will not be same as of already posted answers by previous users. Most of the users who are doing this activity are T.kumar, Gaddam Chethan, Prabhakar ch  and few more. If they will not stop this activity then their account will be deactivated.

Please maintain the decorum of this forum for which it is created for and not make it gift voucher earning website only.
manmath
49 Points
5 years ago
. if we derive this in binomial theorem we get the expansion like this.this the formulae .3+b2b+3ab2+3a is a3the formulae for (a+b)