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What is the equation of the normal to the curve y = sin x at (0, 0)? (a)x =0 (b) y=0 (c)x+y =0 (d)x-y=0
Dear StudentGiven that, y = sin xHence, dy/dx = cos xThus, the slope of the normal = (-1/cos x)@x =0= -1Therefore, the equation of the normal is y-0 = -1(x-0) or x+y=0 the correct solution is option C.Thanks
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