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Under root of all these numbers 999-1000x1001x1002+1 is

Under root of all these numbers 999-1000x1001x1002+1 is 

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Grade:11

1 Answers

Armaan Arora
100 Points
one year ago
answer is c (1000999)
999*1000*1001*1002+1=10,01,99,89,98,001
and root of 10,01,99,89,98,001 is 1000999

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