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Grade: 12th pass
        
Two persons A and B start moving from point P towards Q which are 1400 Km apart. Speed of A is 50 Krn/hr and that of B is 20 Km/hr. How far is A from Q when he meets B for the 22nd time?
3 months ago

Answers : (2)

Arun
23013 Points
							

Total distance travelled by both of them for 22nd meeting = 1400 + (21 * 2 * 1400) = 43 * 1400 
Distance travelled by each will be in proportion of their speed : 
Therefore, distance travelled by A = 50/(50 + 20) * 43 * 1400 = 43000 (Note - Always do complicated calculations at last because things cancel out generally) 
Now, for every odd multiple of 1400, A will be at Q and for every even multiple of 1400 A will be at P. So, at 42000 Km (1400 x 30, even multiple) A will beat P. So at their 22 meeting, A will be 1000 Km from P, therefore, 400 Km from Q.

The question is "How far is A from Q when he meets B for the 22nd time?"

Hence, the answer is 400 km
3 months ago
Vikas TU
9484 Points
							
Distance travelled byA / Distance travelled byB = 50/20 = 5/2 .
Dividing 1400 in the ratio 5: 2, we get 1000 : 400.
First time they meet at 400 km from Q.
On 22nd time , 22*800 - 400 = 17,200 km from **Q**
One to and fro motion from Q is 2800 km
17,200 = 6 *2800 + 1000 km
Therefore, they meet at 1000 km from Q.
3 months ago
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