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Two balls are drawn at random from an urn containing 5 white and 3 red balls. The first ball is not replaced before the second ball is drawn. Find the probability that the first ball is red, conditional on the second ball being red.
i am getting 2/7. can someone pls clarify

shiya , 6 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear student
 
required probability = (3/8 * 2/7) /[(3/8 * 2/7) + (5/8* 3/7)]
 
 = 6/21 = 2/7 is correct answer
 
Regards
Arun

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