Two balls are drawn at random from an urn containing 5 white and 3 red balls. The first ball is not replaced before the second ball is drawn. Find the probability that the first ball is red, conditional on the second ball being red. i am getting 2/7. can someone pls clarify

Question

Arun · Answer

Dear student required probability = (3/8 * 2/7) /[(3/8 * 2/7) + (5/8* 3/7)] = 6/21 = 2/7 is correct answer Regards Arun

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Two balls are drawn at random from an urn containing 5 white and 3 red balls. The first ball is not replaced before the second ball is drawn. Find the probability that the first ball is red, conditional on the second ball being red. i am getting 2/7. can someone pls clarify

Two balls are drawn at random from an urn containing 5 white and 3 red balls. The first ball is not replaced before the second ball is drawn. Find the probability that the first ball is red, conditional on the second ball being red.

i am getting 2/7. can someone pls clarify

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Two balls are drawn at random from an urn containing 5 white and 3 red balls. The first ball is not replaced before the second ball is drawn. Find the probability that the first ball is red, conditional on the second ball being red. i am getting 2/7. can someone pls clarify

Two balls are drawn at random from an urn containing 5 white and 3 red balls. The first ball is not replaced before the second ball is drawn. Find the probability that the first ball is red, conditional on the second ball being red. i am getting 2/7. can someone pls clarify

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Two balls are drawn at random from an urn containing 5 white and 3 red balls. The first ball is not replaced before the second ball is drawn. Find the probability that the first ball is red, conditional on the second ball being red.

i am getting 2/7. can someone pls clarify