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Two balls are drawn at random from an urn containing 5 white and 3 red balls. The first ball is not replaced before the second ball is drawn. Find the probability that the first ball is red, conditional on the second ball being red.i am getting 2/7. can someone pls clarify

shiya , 6 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear student
 
required probability = (3/8 * 2/7) /[(3/8 * 2/7) + (5/8* 3/7)]
 
 = 6/21 = 2/7 is correct answer
 
Regards
Arun

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